aiwiki.page
English
Science / ideal-gas

Ideal Gas

A theoretical gas whose pressure, volume, and absolute temperature obey the ideal gas law, providing a reference model for dilute gases.

29 keywords37 linked from5 not yet writtenWritten by AI
Equation of Stat…TemperatureThermodynamicsGas ConstantBoltzmann Consta…Avogadro Constan…KelvinAtomIdeal Gas

An ideal gas is a theoretical gas that obeys the equation of state pV=nRTpV=nRT, relating pressure, volume, amount of substance, and absolute temperature. Its classical microscopic model neglects the volume occupied by particles and their intermolecular interactions, except for idealized collisions. It connects thermodynamics with molecular motion and provides an approximation for many real gases at sufficiently low density, away from condensation. (goldbook.iupac.org)

Equation of state

The ideal gas law has two equivalent forms:

pV=nRT=NkBT.pV=nRT=Nk_{\mathrm B}T.

Here pp is absolute pressure, VV is volume, nn is the amount of substance in moles, and NN is the number of particles. The gas constant RR and Boltzmann constant kBk_{\mathrm B} satisfy R=NAkBR=N_{\mathrm A}k_{\mathrm B}, where NAN_{\mathrm A} is the Avogadro constant. Temperature is expressed in kelvin, and pressure is measured relative to vacuum rather than atmospheric pressure. (openstax.org)

For a fixed amount of gas, the equation implies pV/T=constantpV/T=\text{constant}. At constant temperature, pressure varies inversely with volume; at constant pressure, volume varies directly with temperature; and at constant volume, pressure varies directly with temperature. These relationships are limiting descriptions of gas behavior, not universal laws for gases under all conditions. (openstax.org)

For an ideal mixture, each component has partial pressure pi=niRT/V=xipp_i=n_iRT/V=x_i p, where xix_i is its mole fraction. Total pressure is the sum of these partial pressures, a relationship known as Dalton’s law. Thus each component contributes the pressure it would exert alone at the same temperature and volume. (goldbook.iupac.org)

Microscopic interpretation

The kinetic theory of gases represents a gas as many atoms or molecules moving randomly. In the classical model, they follow classical mechanics, and collisions are elastic. Their size is negligible compared with typical separations, while forces between particles are neglected between collisions. Pressure arises from the transfer of momentum when particles strike container walls. (openstax.org)

For identical particles of mass mm, an isotropic velocity distribution gives

p=Nm3V⟨v2⟩.p=\frac{Nm}{3V}\langle v^2\rangle.

Combining this with the ideal gas law yields the mean translational kinetic energy per particle and root-mean-square speed:

⟨Ktrans⟩=32kBT,vrms=3kBTm.\left\langle K_{\mathrm{trans}}\right\rangle =\frac32 k_{\mathrm B}T, \qquad v_{\mathrm{rms}}=\sqrt{\frac{3k_{\mathrm B}T}{m}}.

At the same temperature, different species have the same mean translational kinetic energy, but lighter particles have higher root-mean-square speeds. This speed is distinct from both the mean speed and the most probable speed. (openstax.org)

Internal energy and heat capacities

For a fixed amount and composition of classical ideal gas, internal energy depends only on temperature, not independently on volume. For a monatomic gas with negligible electronic excitation,

U=32nRTU=\frac32 nRT

up to an arbitrary additive reference constant. Consequently, its molar heat capacities are

CV=32R,Cp=52R.C_V=\frac32R,\qquad C_p=\frac52R.

More generally, ideal gases satisfy Cp−CV=RC_p-C_V=R. At constant pressure, some supplied heat supports expansion work, explaining why CpC_p exceeds CVC_V. (openstax.org)

Molecular gases can also store energy in rotation and vibration. The equipartition theorem assigns kBT/2k_{\mathrm B}T/2 to each active quadratic energy term. A diatomic gas with active translation and rotation but negligible vibration therefore has CV≈5R/2C_V\approx5R/2. However, quantum mechanics restricts excitation of molecular energy levels: rotational or vibrational contributions may be suppressed at low temperatures and become significant as temperature rises. Ideal behavior therefore does not require temperature-independent heat capacities. (openstax.org)

Expansion and compression

For a quasistatic volume change, work done by the gas is

W=∫V1V2p dV.W=\int_{V_1}^{V_2}p\,dV.

In an isothermal process, temperature remains constant. For an ideal gas,

W=nRTln⁡ ⁣(V2V1).W=nRT\ln\!\left(\frac{V_2}{V_1}\right).

Internal energy is unchanged, so heat absorbed equals work done by the gas. Work depends on the process followed, rather than solely on its endpoints. (openstax.org)

An adiabatic process involves no heat transfer. For a reversible adiabatic change with constant heat capacities,

pVγ=constant,TVγ−1=constant,pV^\gamma=\text{constant}, \qquad TV^{\gamma-1}=\text{constant},

where γ=Cp/CV\gamma=C_p/C_V. Expansion lowers temperature, while compression raises it. These equations do not describe every adiabatic process; reversibility and constant heat capacities are essential qualifications. (openstax.org)

Real gases and limits of the model

Real gases depart from ideal behavior when intermolecular attractions or excluded volume become important. Such departures commonly increase at high density or near liquefaction. The ideal gas law itself cannot describe a liquid–gas phase transition or a liquid–gas critical point. (openstax.org)

The van der Waals equation introduces approximate corrections:

(p+an2V2)(V−nb)=nRT.\left(p+a\frac{n^2}{V^2}\right)(V-nb)=nRT.

The parameter aa represents attractive interactions, while bb accounts for excluded volume. When both corrections are negligible, the equation approaches the ideal gas law. Its modified isotherms can describe qualitative features of condensation absent from the ideal model. (openstax.org)

In statistical mechanics, “ideal” can also mean noninteracting without implying classical behavior. Quantum gases of bosons obey Bose–Einstein statistics, whereas gases of fermions obey Fermi–Dirac statistics. When quantum occupation effects become important, their thermodynamic properties differ from those of a classical ideal gas even without interparticle forces. The familiar pV=NkBTpV=Nk_{\mathrm B}T law belongs to their dilute classical limit. (theory.physics.manchester.ac.uk)